Draw a circle of radius 5cm. Take a point P outside the circle. Construct a pair of tangents from P to the circle without using its centre.

Step1: Take distance 5 cm in compass and draw a circle. Take any point P outside the circle and draw a straight line which cuts the circle at A and B where AB is the chord

Step2: Take distance PA in compass and keep the needle on point P and mark arc to the left of P intersecting the line at C. Hence we have PA = PC

Now we have to draw perpendicular bisector of BC

Step3: Take any distance in compass approximately greater than half of CB and keeping the needle on point C mark arcs above and below CB

Step4: Keeping the distance in the compass same as that of in step3 keep the needle on B and mark arcs intersecting the arcs drawn in step3. Join these intersection points we get the perpendicular bisector of CB at M

Step5: Take distance MB in compass keep the needle on point M and draw a semicircle as shown

Step6: Using protractor draw a line from P perpendicular to CB intersecting the semicircle drawn in step5 at L

Step7: Take distance PL in compass, keep the needle on P and mark arc intersecting the circle at Q and T. Join PT and PQ thus PT and PQ are the required triangles