The diameter of a sphere is decreased by 25%. By what percent does its curved surface area decrease?
Concept Used: Curved Surface Area of Sphere = 4πr2
Radius ![]()
Given: Diameter of the Sphere is decreased by 25%
Assumption:
Let r1 be the initial radius, r2 be the increased radius
Explanation:
Radius (r1) ![]()
New radius (r2) ![]()
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Initial Surface Area = CSA (S1) = 4πr12
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= πd2
Decreased Surface Area = CSA (S2) = 4πr22
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Decrease in surface area = S1 – S2
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Now,
Percentage decrease ![]()
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= 43.75 %
Hence, the decrease in surface area is 43.75%.
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