How many spherical bullets can be made out of a solid cube of lead whose edge measures 44 cm, each bullet being 4 cm in diameter?
Concept Used: Volume of Sphere ![]()
Where r = radius of the sphere
The volume of a cube = a3
Where a = edge of the cube.
In a melting or conversion question, the volume remains same. In given questions.
The volume of cube = Volume of spherical bullets
Given: Edge of cube = 44 cm
Diameter of bullets = 4 cm
Explanation:
Let the Volume of cube = V
Let the volume of one spherical bullet = v
Let the number of bullets = n
Now, according to the question,
V = nv …………..(1)
Now Volume of Cube, V = (44 cm)3
The radius of spherical bullet ![]()
The volume of one spherical bullet ![]()
Putting these values in equation (1) we get,
![]()
![]()
n = 2541
Hence, The number of bullets formed is 2541.
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