Q7 of 48 Page 13

The inner diameter of a circular well is 3.5 m. It is 10 m deep. Find

(i) Its inner curved surface area,


(ii) The cost of plastering this curved surface at the rate of Rs 40 per m2

Concept Used: The curved surface area of cylinder = 2πrh


Where, r = radius of the cylinder


H = height of the cylinder


Given:


Inner Diameter of well = 3.5 m


The depth of well = 10 m


Radius =


Assumption: Let r = radius of the base of the cylinder and h be the height of the cylinder.


Explanation:


Inner radius (r) of circular well = m


= 1.75 m


Depth (h) of circular well = 10 m


(i) Inner curved surface area = 2πrh


= 2 × × 1.75 × 10 m2


= (44 × 0.25 × 10) m2


= 110 m2


Therefore, the inner curved surface area of the circular well is 110 m2.


(ii) Cost of plastering 1 m2 area = Rs 40


Cost of plastering 100 m2 area = Rs (110 × 40)


= Rs 4400


Therefore, the cost of plastering the CSA of this well is Rs. 4400.


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