The inner diameter of a circular well is 3.5 m. It is 10 m deep. Find
(i) Its inner curved surface area,
(ii) The cost of plastering this curved surface at the rate of Rs 40 per m2
Concept Used: The curved surface area of cylinder = 2πrh
Where, r = radius of the cylinder
H = height of the cylinder
Given:
Inner Diameter of well = 3.5 m
The depth of well = 10 m
Radius = ![]()
Assumption: Let r = radius of the base of the cylinder and h be the height of the cylinder.
Explanation:
Inner radius (r) of circular well =
m
= 1.75 m
Depth (h) of circular well = 10 m
(i) Inner curved surface area = 2πrh
= 2 ×
× 1.75 × 10 m2
= (44 × 0.25 × 10) m2
= 110 m2
Therefore, the inner curved surface area of the circular well is 110 m2.
(ii) Cost of plastering 1 m2 area = Rs 40
Cost of plastering 100 m2 area = Rs (110 × 40)
= Rs 4400
Therefore, the cost of plastering the CSA of this well is Rs. 4400.
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