In any triangle ABC, prove the following:

Let a, b, c be the sides of any triangle ABC. Then by applying the sine rule, we get
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⇒ a = k sin A, b = k sin B, c = k sin C
Now,
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Substituting the values from sine rule into the above equation, we get
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But ![]()
And ![]()
And ![]()
Substituting these we get

By canceling the like terms, we get

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Similarly,
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Substituting the values from sine rule into the above equation, we get
![]()
![]()
But ![]()
And ![]()
And ![]()
Substituting these we get

By canceling the like terms, we get

![]()
![]()
Similarly,
![]()
Substituting the values from sine rule into the above equation, we get
![]()
![]()
But ![]()
And ![]()
And ![]()
Substituting these we get

By canceling the like terms, we get

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So the LHS of the given equation, we get
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From equation (i), (ii) and (iii), we get
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Hence proved
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