If
and x lies in the IIIrd quadrant, find the values of
and sin 2x.
Given:
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We know,
cos 2x = 2 cos2 x – 1
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Since,
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So,
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We know,
cos 2x = 1 – 2 sin2 x
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Since,
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So,
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We know,
sin2 x + cos2 x = 1
⇒ sin2 x = 1 – cos2 x
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Since,
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So,
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Now,
sin 2x = 2(sin x)(cos x)
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