If sec (x + α) + sec(x - α) = 2 sec x, prove that cos x
Given: sec (x + α) + sec(x - α) = 2 sec x
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sec (x + α) + sec(x - α) = 2 sec x
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{∵ 2 cos A cos B = cos (A + B) + cos (A – B)}
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{∵ cos 2x = 2 cos2 x – 1}
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{∵ cos 2x = 2 cos2 x – 1}
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Hence Proved
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