Q5 of 158 Page 34

Three dice are thrown simultaneously. What is the probability of getting 15 as the sum?

As 3 dice are thrown. So total possible outcomes = 6×6×6 = 216


For getting 15 as the sum we need this combination-


(5, 5, 5) or (6,4,5) or (6,6,3)


(6, 4, 5) can be arranged in 3! = 6 ways.


(6, 4, 5) can be arranged in (3!)/(2!) = 3 ways


∴ 10 favourable outcomes are possible.


∴ P(E) = 10/216


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