Q6 of 158 Page 33

What is the probability that an ordinary year has 53 Sundays?

given: an ordinary year which includes 52 weeks and one day

formula:


so, we have to determine the probability of that one day being Sunday


Total number of possible outcomes are 7


Therefore n(S)=7


E= {M, T, W, T, F, S, SU}


n(E)=1




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