Q8 of 29 Page 1

Find the approximate change in the value of , when x changes from x = 2 to x = 2.002.

Let


Δx and Δy are very small changes in x and y respectively.


As x changes from 2 to 2.002


x = 2


Δx = 2.002 – 2 = 0.002


The change Δy with change Δx is given by



Let us find


y = x-2




Substitute in (i)



Substitute values x = 2 and Δx = 0.002




Δy = -0.0005


As Δy is negative which implies y decreases.


Hence y decreases by 0.0005 as x goes from 2 to 2.002.


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