If
then prove that x(x+1)2y2+(x+1)2y1=2
To prove that x(x+1)2y2+(x+1)2y1 = 2
We will use
and ![]()
![]()
![]()
![]()
We know that log(a/b) = log a – log b
⇒ y = log (x + 1)2 – log x
As log xn = n log x
⇒ y = 2 log (x + 1) – log x
Differentiate with respect to x
![]()
![]()
![]()
![]()
Differentiate again with respect to x
Using u/v rule
![]()
![]()
![]()
![]()
![]()
![]()
![]()
Multiply (x+1) to both numerator and denominator in
to get,
![]()
![]()
Using (i)
⇒ y2(x + 1)2x = 2 – (x + 1)2y1
⇒ y2(x + 1)2x + (x + 1)2y1 = 2
Hence proved
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.




