Q11 of 50 Page 6

In Fig., if AB || DE, ∠ BAC = 35° and ∠ CDE = 53°, find ∠ DCE.

Given: AB parallel DE, ∠BAC = 35o, ∠CDE = 53o
To Find: ∠DCE


According to the question,


∠BAC = ∠CED (Alternate interior angles)


Therefore,


∠CED = 35o


Now, In Δ DEC,


∠DCE + ∠CED + ∠CDE = 180o (Sum of the interior angles of the triangle)


∠DCE + 35o + 53o = 180o


∠DCE + 88o = 180o


∠DCE = 92o


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