Q15 of 50 Page 6

In Fig, PQ||AB and PR||BC. If ∠QPR = 102°, determine ∠ABC. Give reasons.

AB is produced to meet PR at K

Since, PQ ‖ AB

∠QPR = ∠BKR = 102^o (Corresponding angles)

Since, PR ‖ BC

Therefore,

∠RKB + ∠CBK = 180^o (Co. interior angles)

∠CKB = 180^o – 102^o

= 78^o

In Fig., if AB || CD, EF ⊥ CD and∠ GED = 126°, find ∠ AGE, ∠ GEF and ∠ FGE.

In Fig., find x. Further find ∠BOC, ∠COD and ∠AOD.

In Fig., POQ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR. Prove that ∠ ROS = 1/2 (∠ QOS –∠ POS).

In Fig., lines AB and CD intersect at O. If∠ AOC + ∠ BOE = 70° and ∠ BOD = 40°, find∠ BOE and reflex ∠ COE.