The horizontal distance between two trees of different heights is 60 m. The angle of depression of the top of the first tree when seen from the top of the second tree is 45°. If the height of the second tree is 80 m, find the height of the first tree.
let CE be the height of the first tree
and AB is the height of the second tree.
Given : AB = 80 m
BC = 60 m
To find: The length of CE.
Formula Used:
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Explanation:

In ∆ADE
tan 45° = ![]()
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h = 60m
Therefore, height of the first tree is 80-60 = 20m
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