If the angle of elevation of a cloud from a point 200 m above a lake is 30° and the angle of depression of its reflection in the lake is 60°, then find the height of the cloud above the lake.
To find:
The height of the cloud.
Explanation:

A is the position of the cloud, B is the point 200 m above the lake and F is the reflection in the lake.
Here AE = EF
EF = (m + 200) m
In ΔABC
BC = m cot 30° ……………….1
In Δ BCF
CF = 200 + m +200
= (400 + m) meters
BC = (400 + m) cot 60° ………………….2
From 1 and 2
m cot 30° = (400 + m) cot 60°
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3 m = (400 + m)
m = 200 m
height above the cloud above the lake is (200 + 200) m = 400 m
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