An aeroplane while flying at a height of 3000 m from the ground passes vertically above another aeroplane at an instant when angles of elevation of planes from the same point on the ground are 45° and 60°. Find the vertical distance between the aeroplanes.
Formula Used:
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Explanation:

Let P and Q be two aeroplanes where Q is vertically below P and OP = 3000 m.
Let angles be 60° and 45°.
In ΔAOP and ΔAOQ,
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PQ = OP – OQ
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= 1258.85 m
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