Q26 of 51 Page 13

A spherical ball of radius 3 cm is melted and recast into three spherical balls. The radii of the two of the balls are 1.5 cm and 2 cm respectively. Determine the diameter of the third ball.

Given: Radius of big ball = 3 cm

Radius of first ball = 1.5 cm


Radius of second ball = 2 cm


To find: Diameter of the third ball


Formula Used:


The volume of the sphere =


Explanation:


radius of big ball = 3 cm


So, its volume, v =


The spherical ball of radius 3 cm is melted and recast into three spherical balls.


Let the radius of the third ball be r.


Then, volume of third spherical ball =


Volume of first ball =


Volume of second ball =


The volume of the original spherical ball is equal to that of the total volumes of the three balls.







⇒ r = 2.5 cm


Thus, diameter = 5 cm


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