Q3 of 70 Page 11

Let f, g :R → R be defined by f(x) = 2x + 1 and g (x) = x2 – 2, i∀ x ∈ R, respectively. Then, find g o f.

We have,


gof(x) = g(f(x))


⇒ gof(x) = g(2x+1)


= (2x+1)2 – 2


= (4x2+1+4x) – 2


= 4x2+4x-1


∴ gof = 4x2+4x-1


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