Fill in the blanks in each of the
Let f :R → R be defined by
. Then (f o f o f) (x) = _______
Given that, ![]()
Now, (fofof)(x) = f[f(f(x))]
= ![]()
=
=
=
=![]()
=
= 
= ![]()
∴ (f o f o f) (x) = ![]()
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