Let f :R → R be defined by f (x) = 3x2 – 5 and g : R → R by
. Then g o f is
Given that, f (x) = 3x2 – 5 and ![]()
Now,
gof(x) = g(f(x))
= g(3x2-5)
= ![]()
= ![]()
=![]()
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