A proton and an electron travelling along parallel paths enter a region of uniform magnetic field, acting perpendicular to their paths. Which of them will move in a circular path with higher frequency ?
The frequency of revolution of charge in a perpendicular magnetic field is given as
![]()
Where ν = frequency of revolution of charge
q = charge of particle
B = magnetic field
m = mass of particle
As we can see from formula that frequency is inversely proportional to the mass of the particle.
![]()
We know that mass of electron is less than mass of proton. Therefore, electron will move in a circular path with higher frequency.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.