Evaluate the following:

Given ![]()
Put![]()
⇒ ![]()
⇒
(Concept of partial fraction)
⇒ ![]()
On comparing coefficients of ‘t’ we get
⇒ ![]()
⇒ ![]()
⇒ Now put
back in the above eq.
⇒ ![]()
⇒ ![]()
⇒ Now ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
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