Evaluate the following:

Given ![]()
Let ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ Apply Integration by parts
⇒ ![]()
⇒ ![]()
⇒ Put (2) and (3) in (1)
⇒ ![]()
⇒ ![]()
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