In Fig. 6, find the area of the shaded region. [Use π = 3.14]
(CBSE 2015)
Let the side of big square = A = 14 cm

Let the radius of semicircle,
(Diameter of semicircle, d =
= 4cm)
Let the side of small square = a = 4 cm (Side = Diameter of semicircle
Area of square ABCD = (Side)2 = (A)2 = (14)2 = 196cm2
Area of small square PQRS = (Side)2 = (a)2 = (4)2 = 16cm2
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∴ Required area = (Area of big square – Area of small square – Area of 4 semicircles)
= (196-16-25.12) = 154.88 cm2
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(CBSE 2014)
(CBSE 2014)
(CBSE 2015)