Q6 of 26 Page 1

Find the vector equation of the plane with intercepts 3, -4 and 2 on x, y and z-axis respectively.

Given: intercepts of plane on x, y and z-axis are 3, -4 and 2 respectively


To find: vector equation of the plane


Formula used:


The intercept form of the plane with intercepts a, b and c on x, y and z-axis respectively is given by,



Here a = 3, b = -4 and c = 2


Therefore,





⇒ 4x – 3y + 6z = 12




Hence, the vector equation of the plane is,



More from this chapter

All 26 →
4

Write the position vector of the point which divides the join of points with position vectors and in the ratio
2:1.

 5

Write the number of vectors of unit length perpendicular to both the vectors and

7

Find the coordinates of the point where the line through the points A(3, 4, 1) and B(5, 1, 6) crosses the XZ plane. Also find the angle which this line makes with the XZ plane.

 8

The two adjacent sides of a parallelogram are and Find the two-unit vectors parallel to its diagonals. Using the diagonal vectors, find the area of the parallelogram.