Find the position vector of the foot of perpendicular and the perpendicular distance from the point P with position vector
to the plane
Also find image of P in the plane.
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To find: position vector of the foot of perpendicular and the perpendicular distance from the point P to given plane and the image of P in the plane.
Formula used:
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Therefore,
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Hence, position vector of the foot of perpendicular and the perpendicular distance from the point P to given plane are
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Let Q be the image of the point P to the given plane
PQ will be normal to the plane
Therefore, equation of PQ is
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As Q lies on line PQ, the position vector of Q is
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Let R is mid-point of PQ. Position vector of R is
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R will also lie on the plane.
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Put the value of λ = 1:
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Couldn't generate an explanation.
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