The equation of tangent at (2, 3) on the curve is Find the values of a and b.

Given: The equation of tangent is y = 4x – 5 at (2, 3) on the curve y² = ax³ + b

To find: value of a and b

y² = ax³ + b

Differentiating both sides with respect to x:

Now,

y = 4x – 5

Differentiating both sides with respect to x:

Both the slopes are equal at point (2, 3)

Therefore,

The given point (2, 3) is also lie on the curve y² = ax³ + b

Put the value of a = 2:

Hence, the value of a = 2 and b = 7