Let f : R → R be defined as f(x) = 10x + 7. Find the function g : R → R such that gof = fog =IR. [CBSE 2011]
As we have to find g: R→R such that-
fog = gof = IR
We know that IR represents an identity function.
By identity function we mean that –
I(x) = x
∵ fog(x) = I(x)
⇒ f(g(x)) = x
∵ f(x) = 10x + 7
∴ fog(x) = 10{g(x)} + 7 = x
⇒ 10g(x) = x – 7
∴ g(x) = ![]()
G (x) is defined everywhere on a set of real numbers, and its range is also R.
∴ g: R→R can be defined by g(x) = ![]()
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