If the function f:R → R be given by f(x) = x2 + 2 and g :R → R be given by
find fog and gof and hence find fog (2) and gof (– 3). [CBSE 2014]
f(x) = x2 + 2 and ![]()
let us find fog
⇒ fog = f(g(x))
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Replace x by
in f(x)
![]()
For fog(2) put x = 2
![]()
⇒ fog(2) = 6
Now let us find gof
⇒ gof = g(f(x))
⇒ gof = g(x2 + 2)
Replace x by x2 + 2 in g(x)
![]()
![]()
For gof(-3) put x = -3
![]()
![]()
Hence fog(2) = 6 and ![]()
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