Q22 of 23 Page 3

Given,

OR


Find the inverse of the matrix , by using elementary row transformations.(CBSE 2018)

|A| = 5(–1) + 4(1) = –1


C11 = –1 C21 = 8 C31 = –12


C12 = 0 C22 = 1 C32 = –2


C13 = 1 C23 = –10 C33 = 15





Hence,


OR


Using, AA–1 = I


A = IA











Hence,

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