Write the sum of intercepts cut off by the plane
on the three axes.[CBSE 2016]
The given equation when written in Cartesian form becomes
⇒ 2x + y - z - 5 = 0
⇒ 2x + y - z = 5
Divide throughout by 5 we get
⇒ ![]()
⇒ ![]()
∴ x intercept = a = 5/2
y intercept = b = 1/5
z intercept = c = - 1/5
a + b + c = ![]()
∴ Sum of intercepts = 5/2.
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