Q5 of 34 Page 11

Write the sum of intercepts cut off by the plane on the three axes.[CBSE 2016]

The given equation when written in Cartesian form becomes


2x + y - z - 5 = 0


2x + y - z = 5


Divide throughout by 5 we get




x intercept = a = 5/2


y intercept = b = 1/5


z intercept = c = - 1/5


a + b + c =


Sum of intercepts = 5/2.

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