Find the equation of the plane containing two parallel lines
and
Also, find if the plane thus obtained contains the line
or not. [CBSE 2016]
Given:
![]()
Taking points lying on each of the line a1 = (1, - 1, 0) and a2 = (0, 2, - 1)
Direction ratio of l1 is ![]()
Let the equation of plane through a1 be
a(x - 1) + b(y + 1) + c(z) = 0 …(i) where a, b and c are the direction ratio’s
(0, 2, - 1) lies on it, therefore - a + 3b - c = 0 …(ii)
Line in eq(i) is perpendicular to the line with direction ratio’s 2, - 1, 3
Therefore, 2a - b + 3c = 0 …(iii)
Solving (ii) and (iii), by cross-multiplication, we get,
![]()
Therefore, the equation of plane is
8(x - 1) + (y + 1) - 5z = 0
8x + y - 5z = 7
![]()
Point (2, 1, 2) lies on the line l3
Satisfying this point in the equation of plane to check whether l3 is contained in the plane
8(2) + 1 - 5(2) - 7 = 0
Therefore, the plane contains the given line.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
[CBSE 2017]