Find the distance of the point ( – 1, – 5, – 10) from the point of intersection of the line
and the plane
[CBSE 2018]
Here we have the cartesian equation of a line,
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And, the cartesian equation of a plane,
x – y + z – 5 = 0.
Let Q(
be the point of intersection of line and plane which will satisfy both equation.
(let)
![]()
also![]()
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So, putting the value of
, we get,![]()
![]()
![]()
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And,
![]()
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Q = (2, – 1, 2)
l(PQ) = ![]()
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= 13 units.
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[CBSE 2017]