Q7 of 26 Page 1

Solve for x:

OR


Prove that



Now, we know that,





[taking LCM]




[∵(a + b)2 = a2 + b2 + 2ab & (a – b)2 = a2 + b2 – 2ab]


[∵ (a – b)(a + b) = (a2 – b2)]




On comparing both the sides, we get



⇒ 2(4 – x2) = (4x)(x)


⇒ 8 – 2x2 = 4x2


⇒ 8 = 6x2





OR


Taking LHS, …(i)


Firstly, we convert sin-1 into tan-1


Let



Now, we know that


sin2x + cos2x = 1












Now, we know that,










We know that,






= tan-1(1)




=RHS


Hence Proved


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