Show that the function f given by : 
is discontinuous at ![]()

The function f will be discontinuous at x = a in any of following cases :
(i)
and
exist but are not equal.
(ii)
and
exist and are equal but not equal to f (a).
(iii) f (a) is not defined.
Now, we check the Left-hand limit of f at x = 0

Similarly, right-hand limit of f at x = 0


Thus, ![]()
Hence, f is discontinuous at x = 0
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