Q18 of 45 Page 1

Evaluate :

Let

Put x2 = t




⇒ t = A(t + 9) + B(t + 4)


⇒ t = At + 9A + Bt + 4B


⇒ t = t(A + B) + (9A + 4B)


On comparing the coefficients of t and constant terms from both sides, we get


A + B = 1 …(i)


9A + 4B = 0 …(ii)


From eq. (i), we get


A = 1 – B …(iii)


Now, putting the value of A eq. (ii), we get


9(1 – B) + 4B = 0


⇒ 9 – 9B + 4B = 0


⇒ 9 – 5B = 0


⇒ 5B = 9



So,






Now, we know that,





More from this chapter

All 45 →
16

Show that the function f(x) = |x – 3|, x ∈ |R, is continuous but not differentiable at x = 3.

OR


If x = a sin t and y = a ( cost+logtan t/2 ) find d^2y/dx^2

 17

Evaluate :

OR


Evaluate :

19

Evaluate :

20

If and are two vectors such that then prove that vector is perpendicular to vector