Find the vector equation of the plane passing through three points with position vectors
and
Also, find the coordinates of the point of intersection of this plane and the line ![]()
Let the position vectors of the three points be
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So, the equation of the plane passing through the points
is ![]()

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Now, we know that, In cross product

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…(i)
So, the vector equation of the required plane is ![]()
The equation of the given line is ![]()
Position vector of any point on the give line is
…(ii)
The point (ii) lies on plane (i) if,
![]()
⇒ 9(3 + 2λ) + 3(-1 - 2λ) – 1(-1 + λ) = 14
⇒ 27 + 18λ – 3 - 6λ + 1 – λ = 14
⇒ 11λ + 25 = 14
⇒ 11λ = 14 – 25
⇒ 11λ = -11
⇒ λ = -1
Putting λ = -1 in eq. (ii), we get
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⇒![]()
⇒![]()
Thus, the position vector of the point of intersection of the given line and the plane (i) is
and its coordinates are (1, 1, -2)
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