Q32 of 46 Page 278

Let x1, x2, x3, x4, x5 be the observations with mean m and standard deviation s.

The standard deviation of the observations kx1, kx2, kx3, kx4, kx5 is

Given observations are x1, x2, x3, x4, x5

So the mean of the 5 observations is



∑xi= x1+x2+ x3+x4+x5 =5m……..(i)


And the standard deviation of the 5 observations is



Substituting equation (i) in above equation we get




Now we will find the mean and standard deviation of the observations kx1, kx2, kx3, kx4, kx5, we get


So the mean of these 5 observations is




Substituting value from equation (i), we get



m1=mk…………(iii)


And the standard deviation of the 5 observations is




Substituting equation (iii) in above equation we get





Substituting the value from equation (ii), we get



σ=ks


Hence the standard deviation of new set of observations, i.e., kx1, kx2, kx3, kx4, kx5 is ks.

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