Q36 of 46 Page 278

Consider the first 10 positive integers. If we multiply each number by –1 and then add 1 to each number, the variance of the numbers so obtained is

First 10 positive integers are 1, 2, 3,4 ,5 ,6, 7, 8, 9, 10

on multiplying each number by – 1, we get


- 1, -2, -3, -4, -5, -6, -7, -8, -9, -10


on adding 1 to each of the number, we get


0, - 1, -2, -3, -4, -5, -6, -7, -8, -9


∑xi = 0 -1 -2 -3 -4 -5 -6 -7 -8 -9 = - 45


and


∑ xi2= 02 + (- 1)2 + (-2)2 + (-3)2 + (-4)2 + … + (-9)2


But we know , so the above equation on applying this formula when n=9, we get



Now we know,



Substituting the corresponding values, we get






Now for variance we will square on both sides, we get


σ2=8.25


Hence the variance of the numbers so obtained is 8.25

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