Solve each of the following equations and also check your result in each case:
On cross multiplication
2(a - 8) = 3(a - 3)2a - 16 = 3a - 3
On transposing constant terms to RHS and variables to LHS, we get
2a - 3a = 16 - 9-a = 7
a = -7
Check:
Taking LHS
On substituting a = -7, we get
Taking RHS
On substituting a = -7, we get
We got LHS = RHS
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