The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.
Given: diagonal = 24 m
p1 = 8 m
p2 = 13 m
To find: Area of field
Formula Used: Area of rhombus = 1/2 × d × (p1 + p2)
Explanation:

Area of quadrilateral = ![]()
Area of rhombus = ![]()
Area of rhombus = ![]()
Hence, area of quadrilateral is 252 cm2
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