Show that the product of the areas of the floor and two adjacent walls of a cuboid is the square of its volume.
Let length of cuboid = ![]()
breadth of cuboid = b cm
height of cuboid = h cm
So,
Area of floor = l × b=lb cm2
Product of areas of two adjacent walls = (l × h) × (b × h)
= lbh2 cm2
Product of areas of floor and two adjacent walls = lb × lbh cm6
= l2 b2 h2 =(lbh)2 cm6
= (volume of cuboid)2
Hence Proved.
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