Using binomial theorem, expand each of the following:

To find: Expansion of ![]()
Formula used: (i) ![]()
(ii) (a+b)n = nC0an + nC1an-1b + nC2an-2b2 + …… +nCn-1abn-1 + nCnbn
We have, ![]()
⇒ 5C0(x)5-0 + 5C1(x)5-1
+ 5C2(x)5-2
+ 5C3(x)5-3
+ 5C4(x)5-4
+ 5C5![]()

![]()
⇒

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