Show that the term independent of x in the expansion of
is -252.
To show: the term independent of x in the expansion of
is -252.
Formula Used:
General term, Tr+1 of binomial expansion
is given by,
Tr+1
nCr xn-r yr where
nCr![]()
Now, finding the general term of the expression,
, we get
Tr+1
10Cr![]()
For finding the term which is independent of x,
10-2r=5
r=5
Thus, the term which would be independent of x is T6
T6
10C5![]()
T6
10C5![]()
T6
10C5
T6![]()
T6![]()
T6![]()
T6![]()
T6=252
Thus, the term independent of x in the expansion of
is -252.
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