Find the 5th term from the end in the expansion of
.
To Find : 5th term from the end
Formulae :
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For
,
a=x,
and n=12
As n=12 ,therefore there will be total (12+1)=13 terms in the expansion
Therefore,
5th term from the end = (13-5+1)th i.e. 9th term from the starting.
We have a formula,
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For t9 , r=8
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……….![]()
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Therefore, a 5th term from the end ![]()
Conclusion : 5th term from the end ![]()
Couldn't generate an explanation.
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