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10. Binomial Theorem
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Q29 of 70 Page 371

Find the coefficient of x in the expansion of (1 – 3x + 7x2) (1 – x)16.

To Find : coefficient of x


Formula :


We have a formula,



Therefore, expansion of (1-x)16 is given by,





Now,



Multiplying the second bracket by 1 , (-3x) and 7x2



In the above equation terms containing x are


and -3x


Therefore, the coefficient of x in the above expansion



=-16-3


=-19


Conclusion : coefficient of x =-19


More from this chapter

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27

Show that the ratio of the coefficient of x10 in the expansion of (1 – x2)10 and the term independent of x in the expansion of is 1 : 32.

28

Find the term independent of x in the expansion of (91 + x + 2x3) .

30

Find the coefficient of

(i)x5 in the expansion of (x + 3)8


(ii) x6 in the expansion of .


(iii) x-15 in the expansion of .


(iv) a7b5 in the expansion of (a – 2b)12.


31

Show that the term containing x3 does not exist in the expansion of .

Questions · 70
10. Binomial Theorem
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 A 39 B 39 39 40 A 40 B 40 C 40 41 42 43 44 45 46 47 48 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
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