Given: sin x =
and
<x<
i.e, x lies in the Quadrant II .
To Find: i)sin
ii)cos
iii)tan ![]()
Now, since sin x = ![]()
We know that cos x = ![]()
cos x = ![]()
cos x = ![]()
cos x = ![]()
since cos x is negative in II quadrant, hence cos x = - ![]()
i) sin ![]()
Formula used:
sin
= ![]()
Now, sin
=
=
= ![]()
Since sinx is positive in II quadrant, hence sin ![]()
ii)cos ![]()
Formula used:
cos
= ![]()
now, cos
=
= =
= = ![]()
since cosx is negative in II quadrant, hence cos
= ![]()
iii)tan ![]()
Formula used:
tan x = ![]()
hence, tan
=
=
=
= -![]()
Here, tanx is negative in II quadrant.
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