Prove that

To Prove: ![]()
Taking LHS,
= cosx cos2x cos4x cos8x
Multiply and divide by 2sinx, we get
![]()
![]()
[∵ sin 2x = 2 sinx cosx]
Multiply and divide by 2, we get
![]()
We know that,
sin 2x = 2 sinx cosx
Replacing x by 2x, we get
sin 2(2x) = 2 sin(2x) cos(2x)
or sin 4x = 2 sin 2x cos 2x
![]()
Multiply and divide by 2, we get
![]()
We know that,
sin 2x = 2 sinx cosx
Replacing x by 4x, we get
sin 2(4x) = 2 sin(4x) cos(4x)
or sin 8x = 2 sin 4x cos 4x
![]()
Multiply and divide by 2, we get
![]()
We know that,
sin 2x = 2 sinx cosx
Replacing x by 8x, we get
sin 2(8x) = 2 sin(8x) cos(8x)
or sin 16x = 2 sin 8x cos 8x
![]()
= RHS
∴ LHS = RHS
Hence Proved
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