Prove that
cosec 2x + cot 2x = cot x
To Prove: cosec 2x + cot 2x = cot x
Taking LHS,
= cosec 2x + cot 2x …(i)
We know that,
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Replacing x by 2x, we get
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So, eq. (i) becomes
![]()
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[∵ 1 + cos 2x = 2 cos2x]
[∵ sin 2x = 2 sinx cosx]
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= cot x ![]()
= RHS
Hence Proved
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