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13. Derivative as a Rate Measurer
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Q4 of 78 Page 13

The side of a square is increasing at the rate of 0.1 cm/sec. Find the rate of increase of its perimeter.

The perimeter of a square, with side a, is defined as

P(a)=4a – (1)


Given that , we have to calculate


Differentiating (1) with respect to t, we get



Substituting the values, we get



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The radius of a circle is increasing at the rate of 0.5 cm/sec. Find the rate of increase of its circumference.

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Questions · 78
13. Derivative as a Rate Measurer
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